1500=80x-0.5x^2-(40x+300)

Solution for 1500=80x-0.5x^2-(40x+300) equation:

1500=80x-0.5x^2-(40x+300)

We move all terms to the left:

1500-(80x-0.5x^2-(40x+300))=0


We calculate terms in parentheses: -(80x-0.5x^2-(40x+300)), so:

80x-0.5x^2-(40x+300)

determiningTheFunctionDomain
-0.5x^2+80x-(40x+300)

We get rid of parentheses

-0.5x^2+80x-40x-300

We add all the numbers together, and all the variables

-0.5x^2+40x-300

Back to the equation:

-(-0.5x^2+40x-300)


We get rid of parentheses

0.5x^2-40x+300+1500=0

We add all the numbers together, and all the variables

0.5x^2-40x+1800=0

a = 0.5; b = -40; c = +1800;
Δ = b2-4ac
Δ = -402-4·0.5·1800
Δ = -2000
Delta is less than zero, so there is no solution for the equation